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Each parallel wire has the same voltage as the entire circuit. In purely resistive series ac circuits all the voltage drops across the resistors can be added together to find the total circuit voltage as all the voltages are in phase with each other.

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As the voltage across a resistor is given as v r ir the instantaneous voltage across the resistor above can also be given as.

Rms voltage drop across resistor. If the rms voltage drop across a 15 k resistor is. Calculate rms voltage drop across r l and c. A 3 v peak to peak signal is placed across the circuit with a frequency of 100 hz.
Use the total voltage to find the voltage across each resistor. If the rms voltage drop across a 15 kw resistor is 16 v the peak current through the resistor is. The voltage drop across the resistor is the same as the voltage of the dc source.
This comes from kirchoffs voltage law which states that all the voltages in a given circuit loop must add up to zero. Consider a series rlc circuit with r 300 ohm l 30 mh 03h and c 5uf 510 6f. Sine wave a has a positive going zero crossing at 450.
Lets say a circuit with two parallel resistors is powered by a 6 volt battery. The voltage across the left resistor is 6 volts and the voltage across the right resistor is 6 volts. The voltage drop across each resistor with total voltage of 12 v and resistances 5 8 and 2 can be calculated as v 1 12 5 5 8 2 v1 4 v 2 12 8 5 8 2 v2 64 v 3 12 2 5 8 2 v3 16.
If you know the voltage across the whole circuit the answer is surprisingly easy.

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